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100(2)=b^2
We move all terms to the left:
100(2)-(b^2)=0
We add all the numbers together, and all the variables
-1b^2+1002=0
a = -1; b = 0; c = +1002;
Δ = b2-4ac
Δ = 02-4·(-1)·1002
Δ = 4008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4008}=\sqrt{4*1002}=\sqrt{4}*\sqrt{1002}=2\sqrt{1002}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{1002}}{2*-1}=\frac{0-2\sqrt{1002}}{-2} =-\frac{2\sqrt{1002}}{-2} =-\frac{\sqrt{1002}}{-1} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{1002}}{2*-1}=\frac{0+2\sqrt{1002}}{-2} =\frac{2\sqrt{1002}}{-2} =\frac{\sqrt{1002}}{-1} $
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